(3x^-2/8y^-5)^-2

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Solution for (3x^-2/8y^-5)^-2 equation: 


D( x )

((3*x^-2)/8)*y^-5 = 0

x = 0

((3*x^-2)/8)*y^-5 = 0

((3*x^-2)/8)*y^-5 = 0

3/8*x^-2*y^-5 = 0 // : 3/8*y^-5

x^-2 = 0

x należy do O

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(((3*x^-2)/8)*y^-5)^-2 = 0

64/9*x^4*y^10 = 0 // : 64/9*y^10

x^4 = 0

x = 0

x in { 0} 

x belongs to the empty set

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